Off-Topic Discussions

You've really gotta give better rules....

what about (4!^(3+1)!)^2?

it equals approximately 177885112200000000000000000000000000000000000000000000000000000000
0

or even 4!^(3+2+1)! = (24^720)

[Edited by robofingers, 12/21/2009 5:57:31 PM]

Ok...

Here is the answer, 321^4

BIG NUMBERS ALERT!

Wow. He got his own question wrong.


321^4 = 10,617,447,681

4^321 = 1.82497625 × 10^193

Or in layman's terms:
(1,824,976,250,000,000,000,000,000,000,000,000,
000,000,000,000,000,000,000,000,000,000,000,000,
000,000,000,000,000,000,000,000,000,000,000,000,
000,000,000,000,000,000,000,000,000,000,000,000,
000,000,000,000,000,000,000,000,000,000,000,000,
000,000,000,000,000,000,000,000)

I"m pretty sure Ten Billion, six hundred and seventeen million, four hundred and forty-seven thousand and six hundred and eighty-one is smaller than One trillion, eight hundred and twenty-four billion, nine hundred and seventy-six million, two hundred and fifty thousand trillion trillion trillion trillion trillion trillion trillion trillion trillion trillion trillion trillion million.

Sorry to bust your bubble... but 3^421 > 4^321
besides, I assumed that there had to be an expression between each number. If there doesn't, 4321! would be the largest (4321* 4320*4319 etc.) by... well, by a lot.

How about (2^(3^41))!
That's the highest I can think of if the only rule is you have to use each number once.

I wasn't saying that 4^321 was the biggest, just that 4^321 was bigger than 321^4.

Rayso said that 321^4 was the biggest, I was just proving him wrong.